Poetry / June 2017 (Issue 36: Writing Japan)

Teacher Say Must Show Working

by Alvin Pang

At the cafe in Kyoto, 毅+明 look at owls。 毅 f(look) var(Owl|various) + 明 f(look)
var(Owl|various)。 Also: 毅 f(pet) var(Cat|Bengal) + 明 f(pet) var(Cat|Bengal) on a
combo ticket, because (f(price) var(Owl) + var(Cat)) < f(price) var(Owl) + f(price)
var(Cat)。 Time=Time+var(x)。 Afterwards the rain, f(rain) var(duration|hour|1)。
Then f(wefie) @ "the giant crab" loc(Kani Doraku|Kyoto) with umbrellas。Then dinner
at Mishima-Tei = f(sukiyaki) var(Beef|Kobe|A5)。 Does 毅+var(joy|y) = 明+var(joy|y)?
Calculate to the nearest dollar。


毅 swims 23% faster than 明。 In other words: 毅 f(swim) > 明 f(swim)
var(speed)*1.23。 毅 waits Time+wait(var(Minute|1)) for 明 to catch up, thinks 明 is
making fun, that 明 f(fun)=f(swim)-var(speed|delay|arbitrary)。 But 明 is only trying to
f(breathe) and f(swim) and 明 var(lungcapacity) < 毅 var(lungcapacity) because 明
var(age|years) = 毅 var(age|years)+24 and past the threshold where it matters。
Determine delay until next 毅 f(swim) || 明 f(swim)。


毅 & 明 share a few strands of acid + a stack of need。 To elaborate: 毅 =
f(undefinedfunction) var(DNA|undefined subvariable)明; 毅 f(need) 明 > 明 f(need) 毅,
but paradox of the equation = 明-毅 > 毅-明。 To solve, let 毅 be 毅, not var(明)。 Let 明
approach 0 as Time=Time+var(x)。 Find (x) first. Bury (x)。
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